Growth estimates for a Dirichlet series and its derivative

  • S.I. Fedynyak Ukrainian Catholic University, Lviv, Ukraine
  • P.V. Filevych Lviv Polytechnic National University, Lviv, Ukraine
Keywords: analytic function, maximum modulus, maximum modulus point, zero set


Let $A\in(-\infty,+\infty]$, $\Phi$ be a continuous function on $[a,A)$ such that for every $x\in\mathbb{R}$ we have
$x\sigma-\Phi(\sigma)\to-\infty$ as $\sigma\uparrow A$, $\widetilde{\Phi}(x)=\max\{x\sigma -\Phi(\sigma)\colon \sigma\in [a,A)\}$ be the Young-conjugate function of $\Phi$, $\overline{\Phi}(x)=\widetilde{\Phi}(x)/x$ for all sufficiently large $x$, $(\lambda_n)$ be a nonnegative sequence increasing to $+\infty$, $F(s)=\sum a_ne^{s\lambda_n}$ be a Dirichlet series absolutely convergent in the half-plane $\operatorname{Re}s<A$, $M(\sigma,F)=\sup\{|F(s)|\colon \operatorname{Re}s=\sigma\}$ and $G(\sigma,F)=\sum |a_n|e^{\sigma\lambda_n}$ for each $\sigma<A$. It is proved that if $\ln G(\sigma,F)\le(1+o(1))\Phi(\sigma)$, $\sigma\uparrow A$, then the inequality
\varlimsup_{\sigma\uparrow A}\frac{M(\sigma,F')}{M(\sigma,F)\overline{\Phi}\,^{-1}(\sigma)}\le1
holds, and this inequality is sharp. % Abstract (in English)


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How to Cite
Fedynyak S, Filevych P. Growth estimates for a Dirichlet series and its derivative. Mat. Stud. [Internet]. 2020Mar.17 [cited 2021Oct.16];53(1):3-12. Available from: